# leetcode\_195

Given a text file file.txt, print just the 10th line of the file.

Example:

Assume that file.txt has the following content:

Line 1 Line 2 Line 3 Line 4 Line 5 Line 6 Line 7 Line 8 Line 9 Line 10 Your script should output the tenth line, which is:

Line 10 Note: 1. If the file contains less than 10 lines, what should you output? 2. There's at least three different solutions. Try to explore all possibilities.

## Solutions

1. **head/tail**
2. tail -n+num output lines starting with num'line(1-basesd)

```bash
tail -n+10 file.txt | head -1
```

OR

```bash
# cat file.txt | wc -l
# grep -c "" file.txt
if [ `wc -l file.txt|cut -d " " -f 1` -ge 10 ]
then
    echo `head -n 10 file.txt| tail -n 1`
fi
```