leetcode_367
Given a positive integer num, write a function which returns True if num is a perfect square else False.
Note: Do not use any built-in library function such as sqrt.
Example 1:
Input: 16
Output: true
Example 2:
Input: 14
Output: false
Solutions
The problem is equivalent to calculating the square root of the given number.
See problem 69 for details.
newton's method
class Solution {
public:
bool isPerfectSquare(int num) {
long root = num;
while (root * root > num) {
root = (root + num / root) / 2;
}
return root * root == num;
}
};
binary search
class Solution {
public:
bool isPerfectSquare(int num) {
int lo = 1, hi = num;
while (lo < hi) {
long mid = lo + ((hi - lo) >> 1);
if (mid * mid < num)
lo = mid + 1;
else
hi = mid;
}
return (long)lo * lo == num;
}
};
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